A is a subset of B

**dwsmith** · Oct 9th 2011, 10:03 AM

Prove that if A is a subset of B, then $<A>\leq $ .

Let $|A|=n \ \text{and} \ |B|=m$

$m\geq n$

$<A>=\{e,a,a^2,\cdots, a^{n-1}\}$

$=\{e,b,b^2,\cdots, b^{m-1}\}$

Can I just since |A| less than or equal to |B|, <A> is a subgroup of ?

**Swlabr** · Oct 10th 2011, 01:26 AM

Originally Posted by dwsmith

Prove that if A is a subset of B, then $<A>\leq $ .

Let $|A|=n \ \text{and} \ |B|=m$

$m\geq n$

$<A>=\{e,a,a^2,\cdots, a^{n-1}\}$

$=\{e,b,b^2,\cdots, b^{m-1}\}$

Can I just since |A| less than or equal to |B|, <A> is a subgroup of ?

What is the written down-definition for $\langle X\rangle$ ? This all follows quite quickly once you know this...

**HallsofIvy** · Oct 10th 2011, 06:38 AM

Frankly what you have written makes little sense. If A and B are sets then " $\{e, a, a^2, ..., a^{n-1}\}$ " is meaningless because there is no operation in a set. Apparently you are talking about groups, not sets. But even then you have to define <A>. You appear to mean a sub-group generated by a single element of the group but which element? Or are you assuming from the start that A and B are themselves generated by a single element?

**Swlabr** · Oct 10th 2011, 06:47 AM

Originally Posted by HallsofIvy

Frankly what you have written makes little sense. If A and B are sets then " $\{e, a, a^2, ..., a^{n-1}\}$ " is meaningless because there is no operation in a set. Apparently you are talking about groups, not sets. But even then you have to define <A>. You appear to mean a sub-group generated by a single element of the group but which element? Or are you assuming from the start that A and B are themselves generated by a single element?

What he means is $A\subset B\subset G$ , and he requires to prove that $\langle A\rangle\leq \langle B\rangle$ . However, this is clear by the very definition of $\langle X\rangle$ !

Thread: A is a subset of B

LinkBack

Thread Tools

Display

A is a subset of B

Re: A is a subset of B

Re: A is a subset of B

Re: A is a subset of B

Similar Math Help Forum Discussions

[SOLVED] Proof that if A is a subset of P(A), P(A) is a subset of P(P(A))

Proof on Openness of a Subset and a Function of This Subset

subset help

subset U subset is NOT subspace of Superset?

Is X a subset of X * Y