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Math Help - prove: restriction of an operator to invariant subspace is diagolizable?

  1. #16
    MHF Contributor Drexel28's Avatar
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    Re: prove: restriction of an operator to invariant subspace is diagolizable?

    Quote Originally Posted by skybluesea2010 View Post
    Right.
    So, what does the set of eigenspaces look like for a diagonalizable operator?
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  2. #17
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    Re: prove: restriction of an operator to invariant subspace is diagolizable?

    Do you mean they are linearly independent?
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  3. #18
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    Re: prove: restriction of an operator to invariant subspace is diagolizable?

    they are linearly independent. is this what you mean?
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