Prove that for all fixed such that k isn't 0 the map defined by is an automorphism of .

So I need to show it is an isomorphism. I am having a problem with the homomorphism part though.

Let . but .

What do I need to do?

Results 1 to 6 of 6

- October 7th 2011, 01:01 PM #1

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 5

- October 7th 2011, 01:10 PM #2

- October 7th 2011, 01:12 PM #3

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 5

- October 7th 2011, 01:14 PM #4

- October 7th 2011, 10:48 PM #5

- Joined
- Mar 2011
- Posts
- 40

- October 7th 2011, 11:00 PM #6

- Joined
- Mar 2011
- From
- Tejas
- Posts
- 3,397
- Thanks
- 760

## Re: Q\to Q by q\to kq

in dwsmith's defense, it is bad form to speak of "the group Q". a group is not merely a set, but a set and a binary operation. failure to specify the intended binary operation requires an unwarranted amount of mysticism on the student's part.