what is the difference between the jordan form of matrices A

and diagonal block matrices similar to A

?

Printable View

- Oct 4th 2011, 07:25 AMtransgalacticjordan block question
what is the difference between the jordan form of matrices A

and diagonal block matrices similar to A

? - Oct 4th 2011, 09:56 AMFernandoRevillaRe: jordan block question
Difference, in what terms? For example

$\displaystyle A\sim J=\begin{bmatrix}{\lambda}&{1}&{0}\\{0}&{\lambda}& {1}\\{0}&{0}&{\lambda}\end{bmatrix}\Rightarrow A\sim K=\begin{bmatrix}{\lambda}&{2}&{0}\\{0}&{\lambda}& {3}\\{0}&{0}&{\lambda}\end{bmatrix}$

$\displaystyle J$ is the Jordan form of $\displaystyle A$, $\displaystyle K$ is a diagonal block matrix similar to $\displaystyle A$ but it is not its Jordan form. - Oct 4th 2011, 01:08 PMtransgalacticRe: jordan block question
because of the 2 ,3 on the smaller diagonal

? - Oct 4th 2011, 10:50 PMFernandoRevillaRe: jordan block question