Generators of are correct?
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Originally Posted by dwsmith Generators of are correct? No! Generators of are and .
Originally Posted by alexmahone No! Generators of are and . No? I just listed 1 and -1 too.
Originally Posted by dwsmith No? I just listed 1 and -1 too. You listed .
Originally Posted by alexmahone You listed . Generating set of a group - Wikipedia, the free encyclopedia
Originally Posted by dwsmith Generating set of a group - Wikipedia, the free encyclopedia denotes the subgroup generated by . So, It doesn't make sense to say that the generators of are and , which is what you essentially did.
Last edited by alexmahone; Oct 3rd 2011 at 04:29 PM.
Originally Posted by alexmahone is the subgroup generated by , which is . Similarly, is the subgroup generated by , which is . It doesn't make sense to say that the generators of are and , which is what you essentially did. "The integers under addition are an example of an infinite group which is finitely generated by both <1> and <−1>" Paragraph 1 after the contents
Originally Posted by dwsmith "The integers under addition are an example of an infinite group which is finitely generated by both <1> and <−1>" Paragraph 1 after the contents Not any more. (I've fixed that error now.) In general, Wikipedia is not a good place to learn maths from.
See Example 1.4 of http://www.math.uconn.edu/~kconrad/b...ory/genset.pdf.
Originally Posted by alexmahone See Example 1.4 of http://www.math.uconn.edu/~kconrad/b...ory/genset.pdf. http://www.csus.edu/indiv/z/zhongk/chap4hw.pdf number 23
Originally Posted by dwsmith http://www.csus.edu/indiv/z/zhongk/chap4hw.pdf number 23 Number 23 says that , which is what I said in post #6.