1. ## Simple question

Generators of $\mathbb{Z}$ are $<1> \ \text{and} \ <-1>$ correct?

2. ## Re: Simple question

Originally Posted by dwsmith
Generators of $\mathbb{Z}$ are $<1> \ \text{and} \ <-1>$ correct?
No! Generators of $\mathbb{Z}$ are $1$ and $-1$.

3. ## Re: Simple question

Originally Posted by alexmahone
No! Generators of $\mathbb{Z}$ are $1$ and $-1$.
No? I just listed 1 and -1 too.

4. ## Re: Simple question

Originally Posted by dwsmith
No? I just listed 1 and -1 too.
You listed $<1> \ \text{and} \ <-1>$.

5. ## Re: Simple question

Originally Posted by alexmahone
You listed $<1> \ \text{and} \ <-1>$.

Generating set of a group - Wikipedia, the free encyclopedia

6. ## Re: Simple question

$$ denotes the subgroup generated by $n$.

So, $<1>=<-1>=\mathbb{Z}$

It doesn't make sense to say that the generators of $\mathbb{Z}$ are $\mathbb{Z}$ and $\mathbb{Z}$, which is what you essentially did.

7. ## Re: Simple question

Originally Posted by alexmahone
$<1>$ is the subgroup generated by $1$, which is $Z^{+}$. Similarly, $<-1>$ is the subgroup generated by $-1$, which is $Z^{-}$.

It doesn't make sense to say that the generators of $\mathbb{Z}$ are $Z^{+}$ and $Z^{-}$, which is what you essentially did.

"The integers under addition are an example of an infinite group which is finitely generated by both <1> and <−1>"

Paragraph 1 after the contents

8. ## Re: Simple question

Originally Posted by dwsmith
"The integers under addition are an example of an infinite group which is finitely generated by both <1> and <−1>"

Paragraph 1 after the contents
Not any more. (I've fixed that error now.)

In general, Wikipedia is not a good place to learn maths from.

11. ## Re: Simple question

Originally Posted by dwsmith
Number 23 says that $<-1>=<1>=\mathbb{Z}$, which is what I said in post #6.