<0,0,0,1> <0,0,2,1> <0,3,2,1> <0,1,-1,1> are vectors w = 0 2z + w = 0 3y + 2z +w = 0 y - w +z=0 How do I find other solutions besides w=z=y=x=0 since I know these vectors are linearly dependent.
Follow Math Help Forum on Facebook and Google+
What makes you think that x=0?
Yes is a free variable. So (where is a varying parameter) .
Last edited by tukeywilliams; September 13th 2007 at 12:02 AM.
View Tag Cloud