<0,0,0,1> <0,0,2,1> <0,3,2,1> <0,1,-1,1> are vectors w = 0 2z + w = 0 3y + 2z +w = 0 y - w +z=0 How do I find other solutions besides w=z=y=x=0 since I know these vectors are linearly dependent.
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What makes you think that x=0?
Yes $\displaystyle x $ is a free variable. So $\displaystyle x = t $ (where $\displaystyle t $ is a varying parameter) $\displaystyle y = z = w = 0 $.
Last edited by tukeywilliams; Sep 13th 2007 at 12:02 AM.
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