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Math Help - difficult systems of equations

  1. #1
    Junior Member
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    difficult systems of equations

    <0,0,0,1> <0,0,2,1> <0,3,2,1> <0,1,-1,1> are vectors

    w = 0
    2z + w = 0
    3y + 2z +w = 0
    y - w +z=0

    How do I find other solutions besides w=z=y=x=0 since I know these vectors are linearly dependent.
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  2. #2
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    Opalg's Avatar
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    What makes you think that x=0?
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  3. #3
    Senior Member tukeywilliams's Avatar
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    Yes  x is a free variable.

    So  x = t (where  t is a varying parameter)

     y = z = w = 0 .
    Last edited by tukeywilliams; September 13th 2007 at 12:02 AM.
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