<0,0,0,1> <0,0,2,1> <0,3,2,1> <0,1,-1,1> are vectors

w = 0

2z + w = 0

3y + 2z +w = 0

y - w +z=0

How do I find other solutions besides w=z=y=x=0 since I know these vectors are linearly dependent.

Printable View

- Sep 13th 2007, 12:06 AMlord12difficult systems of equations
<0,0,0,1> <0,0,2,1> <0,3,2,1> <0,1,-1,1> are vectors

w = 0

2z + w = 0

3y + 2z +w = 0

y - w +z=0

How do I find other solutions besides w=z=y=x=0 since I know these vectors are linearly dependent. - Sep 13th 2007, 12:48 AMOpalg
What makes you think that x=0?

- Sep 13th 2007, 12:50 AMtukeywilliams
Yes is a free variable.

So (where is a varying parameter)

.