Ok so for the first part of this question I was required to find the inverse of A =
(1 3 3)
(1 4 3)
(1 3 4)
I did this and got:
(1 0 0)
(0 1 0)
(0 0 1)
Now I am required to "use result from first part" to find the solution to this system:
x + 3y + 3z= 3
x + 4y + 3z = 1
x + 3y + 4z = -2
Would I substitute x=1, y=1, z=1? I am not sure at all what to do