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Math Help - Using a result to find solution to a system.

  1. #1
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    Using a result to find solution to a system.

    Ok so for the first part of this question I was required to find the inverse of A =

    (1 3 3)
    (1 4 3)
    (1 3 4)

    I did this and got:

    (1 0 0)
    (0 1 0)
    (0 0 1)


    Now I am required to "use result from first part" to find the solution to this system:

    x + 3y + 3z= 3
    x + 4y + 3z = 1
    x + 3y + 4z = -2


    Would I substitute x=1, y=1, z=1? I am not sure at all what to do
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  2. #2
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    Re: Using a result to find solution to a system.

    Quote Originally Posted by kmjt View Post
    Ok so for the first part of this question I was required to find the inverse of A =

    (1 3 3)
    (1 4 3)
    (1 3 4)

    I did this and got:

    (1 0 0)
    (0 1 0)
    (0 0 1)


    Now I am required to "use result from first part" to find the solution to this system:

    x + 3y + 3z= 3
    x + 4y + 3z = 1
    x + 3y + 4z = -2


    Would I substitute x=1, y=1, z=1? I am not sure at all what to do
    \displaystyle \left[\begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{matrix}\right] is NOT the inverse of \displaystyle \left[\begin{matrix}1&3&3 \\ 1&4&3\\ 1 & 3 & 4\end{matrix}\right], it is the identity matrix. An inverse matrix is defined to be the matrix you multiply by to GET to the identity matrix.
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