Ok so for the first part of this question I was required to find the inverse of A =

(1 3 3)

(1 4 3)

(1 3 4)

I did this and got:

(1 0 0)

(0 1 0)

(0 0 1)

Now I am required to "use result from first part" to find the solution to this system:

x + 3y + 3z= 3

x + 4y + 3z = 1

x + 3y + 4z = -2

Would I substitute x=1, y=1, z=1? I am not sure at all what to do