Thread: Calculate the solution using X = A^-1B

I wrote the system of equations in the form AX = B, however how would I go about calculating the solution using the equation X = A^-1B?

Go to this web page.
Scroll about half way down.
You will find material of inverses of a matrix.

You would find the inverse of the matrix and multiply by it! That is exactly what means.

The inverse of the two by two matrix [tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix} is where , the determinant of the matrix. Be sure to do the multiplication in the order shown.

if

then so

, that is:

.

so if A is indeed invertible, then calculating tells you which vector "X" is.