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I wrote the system of equations in the form AX = B, however how would I go about calculating the solution using the equation X = A^-1B? (Headbang)

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- September 24th 2011, 06:03 AMkmjtCalculate the solution using X = A^-1B
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I wrote the system of equations in the form AX = B, however how would I go about calculating the solution using the equation X = A^-1B? (Headbang) - September 24th 2011, 06:17 AMPlatoRe: Calculate the solution using X = A^-1B
Go to this web page.

Scroll about half way down.

You will find material of inverses of a matrix. - September 24th 2011, 11:20 AMHallsofIvyRe: Calculate the solution using X = A^-1B
You would find the inverse of the matrix and multiply by it! That is exactly what means.

The inverse of the two by two matrix [tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix} is where , the determinant of the matrix. Be sure to do the multiplication in the order shown. - September 24th 2011, 04:52 PMDevenoRe: Calculate the solution using X = A^-1B
if

then so

, that is:

.

so if A is indeed invertible, then calculating tells you which vector "X" is.