Thread: Finding invertible and diagonal matrix

Originally Posted by farmeruser1

Let A be a 3x3 Matrix (Im not sure how to make a matrix)

A=
-1 0 1
5 3 2
6 0 4

[TEX]A=\left(\begin{matrix} -1 &0 &1\\5 &3 &2\\6 &0 4\end{matrix}\right)[/TEX] gives

An n by n matrix is "diagonalizable" if and only if it has n independent eigenvectors. If that is true then "D" is the diagonal matrix having A's eigenvalues on its diagonal and "P" is the matrix whose columns are the corresponding eigenvectors (if eigenvalue [tex]\lambda[/itex] is at the first row, the first column of D is the eigenvector corresponding to , etc.