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**H12504106** Let $\displaystyle M=\begin{pmatrix} A & B \\ O & C\end{pmatrix}$, where A and C are square matrix. Show that det(M)=det(A)det(C)

I have the following idea but i dont have a concrete proof. We can perform elementary row operations on the matrix M. Eventually A and C will be a upper triangular matrix. Hence det(A) and det(C) will just be the product of their diagonal entries. On the other hand, M will also become an upper triangular matrix after the elementary row operations. Therefore, det(M)=product of its diagonal entries=product of diagonal entries of A * product of diagonal entries of C=det(A)det(C).