G is a group and and .

Prove

I don't see how to show this. Multiplying by the inverse would just use the property I have to prove.

Results 1 to 3 of 3

- Sep 9th 2011, 06:44 PM #1

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 10

- Sep 9th 2011, 06:53 PM #2

- Sep 10th 2011, 04:41 AM #3

- Joined
- Apr 2005
- Posts
- 19,471
- Thanks
- 2893