Sum of dimensions of eigenspaces?

How do I calculate the sum of dimensions of eigenspaces to evaluate whether or not a matrix is diagonalisable?

E.g. dim(span{(-2 0 1)}) + dim(span{(1 0 0)}) ?

They're supposed to be written as vectors but I can't work out how to do that so I apologise for that. Thank you!

Re: Sum of dimensions of eigenspaces?

Quote:

Originally Posted by

**virussss123** How do I calculate the sum of dimensions of eigenspaces to evaluate whether or not a matrix is diagonalisable?

E.g. dim(span{(-2 0 1)}) + dim(span{(1 0 0)}) ?

They're supposed to be written as vectors but I can't work out how to do that so I apologise for that. Thank you!

I'm confused. Can you restate the question.

Re: Sum of dimensions of eigenspaces?

Quote:

Originally Posted by

**virussss123** How do I calculate the sum of dimensions of eigenspaces to evaluate whether or not a matrix is diagonalisable?

E.g. dim(span{(-2 0 1)}) + dim(span{(1 0 0)}) ?

They're supposed to be written as vectors but I can't work out how to do that so I apologise for that. Thank you!

dim(span{(-2 0 1)}) + dim(span{(1 0 0)}) = 1 + 1 = 2

Re: Sum of dimensions of eigenspaces?

I'm trying to find out if a matrix A is diagonalisable. In order to do this, I need to work out the sum of dimensions of eigenspaces.

Does that make it clearer?

Re: Sum of dimensions of eigenspaces?

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Originally Posted by

**alexmahone** dim(span{(-2 0 1)}) + dim(span{(1 0 0)}) = 1 + 1 = 2

Why does it end up as 1+1?

Re: Sum of dimensions of eigenspaces?

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Originally Posted by

**virussss123** Why does it end up as 1+1?

For any non-zero vector v, dim(span(v)) = 1 because a basis of span(v) is {v}, which contains only one vector.

Re: Sum of dimensions of eigenspaces?

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Originally Posted by

**alexmahone** For any vector v, dim(span(v)) = 1 because a basis of span(v) is {v}, which contains only one vector.

That makes sense, thanks. So if there are 3 vectors, would it make the sum 3? i.e if there are 3 eigenvalues resulting in 3 different eigenspaces, would the sum of dimensions of eigenspaces be 3? Thank you

Re: Sum of dimensions of eigenspaces?

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Originally Posted by

**virussss123** So if there are 3 vectors, would it make the sum 3?

I guess so, as long as none of the vectors is the zero vector, in which case dim(span(v)) = 0.

Re: Sum of dimensions of eigenspaces?

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Originally Posted by

**alexmahone** I guess so, as long as none of the vectors is the zero vector, in which case dim(span(v)) = 0.

That answers everything. Thank you alexmahone!