let A=[aij],where aij=uivj 1<=i<=n and 1<=j<=n and ui,vj belong to R satisfies A^5=16A find trace(A)
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Hint: Denoting $\displaystyle U=\begin{pmatrix}u_1\\ \vdots\\{u_n}\end{pmatrix},\;V=\begin{pmatrix}v_1, v_2,\hdots,v_n\end{pmatrix}$ we verify $\displaystyle A=UV$ and $\displaystyle A^5=(u_1v_1+\ldots+u_nv_n)^4A=(\textrm{tr}A)^4A$
whats the final answer is it 11
Originally Posted by prasum whats the final answer is it 11 Why?
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