I am trying to determine the eigenvalues of A
A =
(6 0 2)
(0 7 0)
(2 0 3)
Which is a 3x3 matrix.
So far I have.
The characteristic equation is det (A-lambda I)=0;
|6-lam 0 2|
|0 7-Lam 0| = 0
|2 0 3-Lam|
I expand the determinant, and obtain
(6-Lam)
|7-lam 0|
|0 3-lam|
-0+
|0 6-Lam| = 0
|2 0 |
Not sure how to simplyfy and factorise this expession.
Can anyone help?