I am trying to determine the eigenvalues of A

A =

(6 0 2)

(0 7 0)

(2 0 3)

Which is a 3x3 matrix.

So far I have.

The characteristic equation is det (A-lambda I)=0;

|6-lam 0 2|

|0 7-Lam 0| = 0

|2 0 3-Lam|

I expand the determinant, and obtain

(6-Lam)

|7-lam 0|

|0 3-lam|

-0+

|0 6-Lam| = 0

|2 0 |

Not sure how to simplyfy and factorise this expession.

Can anyone help?