Image/Column space of a Matrix
I'm really struggling with this question :(. The solutions on it don't seem to match up with everything i've read/googled!
Now, I understand how to get the kernel. But I have no idea what they are doing to get the image basis!
I've looked around on wikipedia etc and read that you take the corresponding columns to the pivots - which to me would mean the basis would be: (1 0 3), (-2, 2, -4)...Not (1; 2; 1); (2; 0; 6)
Please see the pdf attachment for the solutions.
Any help would be appreciated!
Re: Image/Column space of a Matrix