It's correct. M
G is the group of 2x2 invertible upper triangular matrices with real entries. Let H be the normal subgroup such that .
If I have the following surjective homomorphism
such that .
Then by the first isomorphism theorem I have the following isomorphism:
such that
Is this correct?
Thanks for any help
What about:
Let J be the subgroup of such that .
Then we have a surjectrive homomorphism [\bar{f}:G\rightarrow J[/TEX] with kernel H.
So from the first isomorphism theorem we have an isomorphism:
thanks for any help