T is a unitary operator. Prove |<Tv,v>| is less than or equal to <v,v>

Let V be an inner product space of finite dimension over C (complex numbers). Let T be a unitary linear operator from V to V. Prove that:

|<Tv,v>| is less than or equal to <v,v>

My working so far:

Since T is unitary <Tv,Tv>=<v,v>, but I'm not sure if this helps at all since I don't know how to show that |<Tv,v>| <= <Tv,Tv>.

Thanks

Re: T is a unitary operator. Prove |<Tv,v>| is less than or equal to <v,v>

I got the answer:

According to the Cauchy Schwartz inequality:

|<Tv,v>| <= ||Tv||.||v||

T is unitary so:

||Tv||=||v||

So:

|<Tv,v>| <= ||Tv||.||v||=||v||.||v||=<v,v>

QED