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About LinkBacksProve that for all a,b in a ring R,
The hint says use:
Since any integer has a negative, we know
Multiple by b:
How can I showfrom the above?
Interesting approach (I don't have a problem with it). Note thatOriginally Posted by dwsmith
Prove that for all a,b in a ring R,
The hint says use:
Since any integer has a negative, we know
Multiple by b:
How can I show. So the first part follows right away:
.
For the second part, you do pretty much the same thing; however, you start withand then multiply by
on the left:
Then because '=' is transitive, it now follows that
I hope this makes sense.
integer?Prove that for all a,b in a ring R,
The hint says use:
Since any integer has a negative, we know
I think you mean the ring is a group under addition and thus every element in the ring has an additive inverse.
Have you proved thatMultiple by b:
)b=0(b)\Rightarrow ab+(-a)b=0)
for all elements b in the ring?
Your approach is right.How can I show
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