how you got this polinomial
in ordrer to get The characteristic polynomials of A is |A-KI|
i dont have the matrices of A
He showed you how he got the polynomial. The trace and determinant of a matrix show up as particular coefficients of the characteristic polynomial of that matrix.
ok i have two eigen values in 2x2 matric
thus making A diagonisable
but it doesnt say that the digonolised form of A is B
?
Well, by the same exact reasoning, wouldn't also be diagonalizable? And wouldn't and have the same diagonalized forms, since they have the same eigenvalues?
Well, by the same exact reasoning, wouldn't also be diagonalizable? And wouldn't and have the same diagonalized forms, since they have the same eigenvalues?
In general no, by no means. BUT in the very particular case of 2x2 matrices yes.