Hello all,
i am studding linear Algrabra from my finals in about 5 days :-)
I have 2 systems that i dont know exactly how to solve them. Would any1 like to help me solve them ?
I'd like step by step solution if its possible
the 1st system is this one:
dx+y+z=a
x+dy+z=b
x+y+dz=c
where a,b,c Real Numbers
The Second is this one:
ax+by+z=1
x+aby+z=b
x+by+az=1
Where a,b Real Numbers
Please DONT solve them both, just one of them,
so i ll try the second on my own and then i ll post my
solution, so you can correct my mistakes
Thanks alot in advance for your help people , its really important :-)
Yes!
Yes!
Yes! But way to complex things?
I gave you.
You also can solved it with Cramer's rule - Wikipedia, the free encyclopedia.
Good-luck!
Hello again, i solved the first expample in Wikipedia correctly, but i have big trouble in sovling this one, that is more abstract (i mean without numbers). This d, is really confusing me, and theres no inidication if its a real number or something...
here is what i have done so far
ill try now the second equation
edit:
Alright i stuck on second as well -.-
this is what ive done so far, i might be tired and cant see the obvious... unlsess is something else tha requires more knowledge.... tips ?
ax+by+z=1
x+aby+z=b
x+by+az=1
If you subtract the first equation from the second you eliminate z: (1- a)x+ (ab-b)y= b-1.
If you subtract a times the first equation from the third equation you also eliminate z: (1-a^2)x+ (b- ab)y= 1- a
Note that b-ab= -(ab-b) so if you add those two equations, you eliminate y: (1- a^2+ 1- a)x= b-1+ 1- a or
(a^2+ a- 2)x= a- b.
Can you finish that?