For X&Y if Z=200? $\displaystyle Xx+Yy+Zz=\alpha $ $\displaystyle X(x-1)+Y(y-1.5)+Z(z+0.5)=\alpha -350 $ $\displaystyle X(x+0.5)+Y(y-2) } +Z(z+1.5)=\alpha +250 $
Last edited by rushton; May 24th 2011 at 10:34 PM.
Follow Math Help Forum on Facebook and Google+
I made a major mistake in determining the equations above so now its not as complicated and I have solved it. When Z=200 we have X=300 and Y=100
Last edited by rushton; May 24th 2011 at 11:16 PM.
View Tag Cloud