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Math Help - Injective Matrix?

  1. #1
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    Injective Matrix?

    Find the nullspace of
    T =
    1 3 4
    1 4 6
    -1 -1 0

    which i found to be (2,-2,1). Though the second part of the question asks if T is injective? Any ideas?

    sorry about the incorrect format. tried to put it matrix form using latex but have never done in before so couldn't get it working.
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  2. #2
    MHF Contributor FernandoRevilla's Avatar
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    Quote Originally Posted by timb89 View Post
    which i found to be (2,-2,1). Though the second part of the question asks if T is injective? Any ideas?
    A basis of the null space of T is certainly \{(2,-2,1)^t\} . Besides, T((2,-2,1)^t)=T((0,0,0)^t). Conclude.
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