# Math Help - Injective Matrix?

1. ## Injective Matrix?

Find the nullspace of
T =
1 3 4
1 4 6
-1 -1 0

which i found to be (2,-2,1). Though the second part of the question asks if T is injective? Any ideas?

sorry about the incorrect format. tried to put it matrix form using latex but have never done in before so couldn't get it working.

2. Originally Posted by timb89
which i found to be (2,-2,1). Though the second part of the question asks if T is injective? Any ideas?
A basis of the null space of $T$ is certainly $\{(2,-2,1)^t\}$ . Besides, $T((2,-2,1)^t)=T((0,0,0)^t)$. Conclude.