One can easily see that (since it's cyclic).
You can check that with symmetric difference is isomorphic to since it's abelian and for every
Try a few more and see if you can work it out. Things to check are number of subgroups of a given order, number of normal subgroups of a given order, number of elements of a given order, whether the two groups are abelian, whether they are cyclic, etc. are all properties preserved under isomorphism.