Results 1 to 4 of 4

- May 18th 2011, 10:45 PM #1

- Joined
- Nov 2007
- Posts
- 30

## Clarificatoin on R^n -> R^m

Hi, I just wanted to double check something:

function :**R**^n ->**R**^m

When this says that the function takes a vector n and turns it into vector m, does this mean that we take a vector of size 5 lets say [1, 2, 3, 4, 5] and turn it into another vector also of size 5 e.g. [7, 8, 9, 10, 11]? So in other words, both vectors are the same size/?dimension? so the only thing that the change from n to m signifies is that we're changing the values due to the function/transformation? So it doesn't turn it into a column vector or something? (I may also be confusing and interchanging array and vector).

This part seems a bit ambiguous for me.

- May 18th 2011, 11:13 PM #2

- Joined
- Nov 2005
- From
- someplace
- Posts
- 14,972
- Thanks
- 5

- May 19th 2011, 02:55 AM #3

- Joined
- Apr 2005
- Posts
- 18,080
- Thanks
- 2393

- May 19th 2011, 01:33 PM #4

- Joined
- Nov 2007
- Posts
- 30