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Math Help - Least squares error

  1. #1
    Senior Member
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    Apr 2009
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    289

    Least squares error



    I know how to do every part except for part d).

    I know that b-Ax is perpendiular to Ax, ie, the column space of A, but how does that have to do anything with the Q?

    Btw the residual vector b-A\bar{x} is given by (0.40476, 0.79619, -2.51238, 0.47905, 1.37048, -0.65143) the sum is -0.11333 which is approximately 0 due to rounding etc.

    \bar{x} is any least square solution of Ax=b

    any help would be appreciated!

    Thanks!
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  2. #2
    Senior Member
    Joined
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    Does it have something to do with finding the column space of A and then finding b-A\bar{x}... im really not sure can anyone help out?
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