# Thread: Characteristic polynomial for eigenvalues

1. ## Characteristic polynomial for eigenvalues

Hmmmm not sure how to do this question, any help would be appreciated!

2. Originally Posted by usagi_killer

Hmmmm not sure how to do this question, any help would be appreciated!
A) True because every matrix is similar to its transpose and similar matrices have the same characteristic equation

B) True because similar matrices have the same characteristic equation

D) True because clearly zero is an eigenvalue

I narrowed it down, so you can figure out between C and E. Ask back if you can't figure it out--but do try please.

3. Thanks Drexel! I got it, it's E, C is correct since the eigenvalues are the negatives of the original.