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Math Help - Finding the normal vector and the distance of point P to the plane

  1. #1
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    Finding the normal vector and the distance of point P to the plane

    Hi, I'm not sure if I got the right answer to this question, and would really appreciate it if you guys could help me out...

    Find the normal vector to the plane through the points Q= (1,1,0), R= (0,0,3) and S= (2,2,1). Hence find the distance from the point P = (1,0,2) to this plane.


    I ended up with a normal vector of -4i + 4j and the distance of P to the plane as \frac{3}{\sqrt{2}}

    Is that correct? Would really appreciate some confirmation on this one.... cheers!

    rorosingsong
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  2. #2
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    Quote Originally Posted by rorosingsong View Post
    Hi, I'm not sure if I got the right answer to this question, and would really appreciate it if you guys could help me out...

    Find the normal vector to the plane through the points Q= (1,1,0), R= (0,0,3) and S= (2,2,1). Hence find the distance from the point P = (1,0,2) to this plane.


    I ended up with a normal vector of -4i + 4j and the distance of P to the plane as \frac{3}{\sqrt{2}}

    Is that correct? Would really appreciate some confirmation on this one.... cheers!

    rorosingsong
    Dear rorosingsong,

    Your normal vector is correct. But the distance must be, \frac{1}{\sqrt{2}}
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  3. #3
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    Ah, thanks! I'm not sure where I went wrong, but I'll go over my working again. Thanks for the prompt reply! =)
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