symetric difference

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August 19th 2007, 06:51 PM
voidstuff

symetric difference

How is the demonstration of this?

$<br /> (A\bigtriangleup B)\bigtriangleup C = A\bigtriangleup (B\bigtriangleup c)<br />$

knowing that
$<br /> (A\bigtriangleup B) = (A/B)\cup(B/A)<br />$
August 19th 2007, 09:34 PM
red_dog

See here
PlanetMath: proof of the associativity of the symmetric difference operator

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