ok so a^p=a I found x^p -a to be reducible but still having trouble with x^p+a . I know x^p+a = (x+a)^p because Zp is a field with Char=p but not sure where to go from there.
ok so a^p=a I found x^p -a to be reducible but still having trouble with x^p+a . I know x^p+a = (x+a)^p because Zp is a field with Char=p but not sure where to go from there.
You can go from there and have a beer (if you're in USA and if you're over 21...) since you've just proved that x^p + a is a product of p linear
factors and thus reducible, so you're done ( Corona is the best!)