In R3 let S=span((1,2,4)^T)
What is a basis for S^(perpendicular)?
I know that 0=x*y=1y1+2y2+4y3
and that y2 and y3 are free variables so y1=-2y2-4y3
i have then tried to solve for each of the vectors this way but it is not correct.
Please help?
Thank You,
Diggidy