I know the definition of a field but I haven't really studied much algebra. Can someone tell me what this means:

$\displaystyle \mathbb{F}_2[x,y]/(x^r,y^s)$

I know it involves a 2-element field but that's about it.

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- Mar 24th 2011, 08:45 AMJosh146Notation help
I know the definition of a field but I haven't really studied much algebra. Can someone tell me what this means:

$\displaystyle \mathbb{F}_2[x,y]/(x^r,y^s)$

I know it involves a 2-element field but that's about it. - Mar 24th 2011, 09:56 AMDeveno
it's a quotient ring. the "main ring" is the ring of polynomials in x and y, with coefficients in the 2-element field F2 = {0,1}. that ring is being factored via the ideal generated by two polynomials x^r and y^s (that is, any polynomial of the form p(x,y)x^r + q(x,y)y^s is treated as if it was 0, so basically this knocks off all powers of x higher than r-1, and all powers of y higher than s-1).

- Mar 24th 2011, 09:58 AMFernandoRevilla
It is the quotient ring $\displaystyle R/I$ . In this case $\displaystyle R$ is the ring $\displaystyle \mathbb{F}_2[x,y]$ and $\displaystyle I=(x^r.y^s)$ the ideal generated by $\displaystyle x^r$ and $\displaystyle y^s$ .

**Edited**: Sorry, I didn't see**Deveno**'s post.