how do i go about getting the basis, and dimension, of the solution space of Ax=0, where A = [1 0 2 -1 0 1 3 -1 2 0 5 -3]?
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Originally Posted by greg27 how do i go about getting the basis, and dimension, of the solution space of Ax=0, where A = [1 0 2 -1 0 1 3 -1 2 0 5 -3]? 1)Bring it into Row Reduced Echelon Form. 2)Sovle for the "leading 1's". 3)Those solutions in #2 form the solution space.
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