basis of solution space

how do i go about getting the basis, and dimension, of the solution space of Ax=0, where A =
[1 0 2 -1
0 1 3 -1
2 0 5 -3]?

Quote:

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Originally Posted by greg27

how do i go about getting the basis, and dimension, of the solution space of Ax=0, where A =
[1 0 2 -1
0 1 3 -1
2 0 5 -3]?

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1)Bring it into Row Reduced Echelon Form.
2)Sovle for the "leading 1's".
3)Those solutions in #2 form the solution space.