Show that the following matrices form a base for M22.

[3 6] , [0 -1], [0 -8] ,,, [1 0]

[3 -6], [-1 0], [-12 -4], [-1 2]

c1M1+c2M2+c3M3+c4M4=B

c1M1+c2M2+c3M3+c4M4=

[0 0]

[0 0]

c1M1+c2M2+c3M3+c4M4=

[a b]

[c d]

After addition I get:

[1 0]

[0 1]

[c1 0] = [a b]

[0 c4] = [c d]

a=d

b=c

Not linearly independent, but it should be.

Thanks for your help.