I have a problem. I know there is an identity to this group but not sure how to prove it. (Q*,o), where x o y = xy/7 Can anyone help? Thanks
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We require e * a = a. In other words, e * a = ea/7 = a Since we're now in "regular" rational multiplication, cancel the a's. e/7 = 1 e = 7. Check.
Thanks for your help.
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