Prove that the normalizer of is always a subgroup of which contains . Further prove it is the unique largest subgroup in which is normal.

- March 2nd 2011, 07:34 PMjoestevensNormalizer as a subgroup. Unique largest subgroup in which A is normal.
Prove that the normalizer of is always a subgroup of which contains . Further prove it is the unique largest subgroup in which is normal.

- March 2nd 2011, 07:57 PMDrexel28
- March 2nd 2011, 08:07 PMjoestevens