Hi, trying to figure out this question, made a guess at how to do it but ended up with the wrong answer .
I need to find the x and y where A^2 = A.
I tried figuring out A^2 and got:
I set that equal to the original A and took the resulting equations:
x² - 4y - 4x - 8 = x - 4
xy + 2y - 4y + 4 = y + 2
And rearranged/substituted and ended with:
x = 1
y = -2
Unfortunately it seems that wasn't the correct answer. So at this point I'm not really sure how to solve this question, can anyone help with this?