Hi cb220, try not to make it so complex, ignore the elements in the 1st column giving
-4x-8=-4
-4y+4=2
I get x=-1, y=-0.5
Hi, trying to figure out this question, made a guess at how to do it but ended up with the wrong answer .
A =
[x -4]
[y 2]
I need to find the x and y where A^2 = A.
I tried figuring out A^2 and got:
[x²-4y -4x-8]
[xy+2y -4y+4]
I set that equal to the original A and took the resulting equations:
x² - 4y - 4x - 8 = x - 4
xy + 2y - 4y + 4 = y + 2
And rearranged/substituted and ended with:
x = 1
y = -2
Unfortunately it seems that wasn't the correct answer. So at this point I'm not really sure how to solve this question, can anyone help with this?
Thanks!