Find the parametric Equations of the line through the point (3,-2) and parallel to v = (3,1,-2) Is the answer going to be (x-3,y+2,z) = (3t,1t,-2t) x = 3+3t y = -2 + 1t z = -2t OR z = -$\displaystyle z_0$ - 2t
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Originally Posted by flaming Find the parametric Equations of the line through the point (3,-2) and parallel to v = (3,1,-2) Is the answer going to be (x-3,y+2,z) = (3t,1t,-2t) x = 3+3t y = -2 + 1t z = -2t You have the z-coordinate missing above.
the question does not give a z coordinate, that is why i am confused. it just says point (3,-2)
Originally Posted by flaming the question does not give a z coordinate, that is why i am confused. it just says point (3,-2) Then there is no answer. It is a faulty question.
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