Find the parametric Equations of the line through the point (3,-2) and parallel to v = (3,1,-2)

Is the answer going to be

(x-3,y+2,z) = (3t,1t,-2t)

x = 3+3t

y = -2 + 1t

z = -2t

OR

z = - - 2t

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- February 6th 2011, 01:03 PMflamingParametric equation of plane
Find the parametric Equations of the line through the point (3,-2) and parallel to v = (3,1,-2)

Is the answer going to be

(x-3,y+2,z) = (3t,1t,-2t)

x = 3+3t

y = -2 + 1t

z = -2t

OR

z = - - 2t - February 6th 2011, 01:30 PMPlato
- February 6th 2011, 01:35 PMflaming
the question does not give a z coordinate, that is why i am confused. it just says point (3,-2)

- February 6th 2011, 01:38 PMPlato