# Parametric equation of plane

• February 6th 2011, 01:03 PM
flaming
Parametric equation of plane
Find the parametric Equations of the line through the point (3,-2) and parallel to v = (3,1,-2)

Is the answer going to be

(x-3,y+2,z) = (3t,1t,-2t)
x = 3+3t
y = -2 + 1t
z = -2t

OR

z = - $z_0$ - 2t
• February 6th 2011, 01:30 PM
Plato
Quote:

Originally Posted by flaming
Find the parametric Equations of the line through the point (3,-2) and parallel to v = (3,1,-2)
Is the answer going to be
(x-3,y+2,z) = (3t,1t,-2t)
x = 3+3t
y = -2 + 1t
z = -2t

You have the z-coordinate missing above.
• February 6th 2011, 01:35 PM
flaming
the question does not give a z coordinate, that is why i am confused. it just says point (3,-2)
• February 6th 2011, 01:38 PM
Plato
Quote:

Originally Posted by flaming
the question does not give a z coordinate, that is why i am confused. it just says point (3,-2)

Then there is no answer. It is a faulty question.