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Math Help - Normal equation of a plane

  1. #1
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    Normal equation of a plane

    Hey,
    I do not understand whats happening here...
    I have two planes in vector form, x1 = (3,2,-1)t and x2 = (1,0,1) + (1,1,1)s + (3,2,-1)t. I know they are parallel because the (3,2,-1)t part is the same. When trying to find the normal using cross product do i use the vectors (3,2,-1)t and (1,1,1)s ? Thanks.
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  2. #2
    Senior Member BAdhi's Avatar
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    are you sure x1 is a plane?

    i think it's a equation of a line since it's having only one parameter
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  3. #3
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    Ah sorry, x1 is a vector... and x2 is a plane that passes through the points (1,0,1) and (2,1,2) and is parallel to the vector (3,2,-1). So i should be able to use (3,2,-1) and [(2,1,2) - (1,0,1)] as my two vectors for cross product ?
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  4. #4
    Senior Member BAdhi's Avatar
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    yes, that would give you the vector normal to the plane.
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  5. #5
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    EDIT: I will create a new post seeing as its a different question.
    Last edited by Oiler; January 31st 2011 at 01:22 AM.
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