2. Two members of a group, x and y, are said to be "conjugate" if there exists a member of the group, z, such that $zxz^{-1}= y$. That, of course, is the same as saying that $zx= yz$. It is easy to prove that that is an equivalence relation (refexive: x is conjugate to itself by taking z equal to the group identity. symmetric: if x is conjugate to y, so that $zxz^{-1}= y$, then $x= z^{-1}yz= uyu^{-1}$ with $u= z^{-1}$. transitive: if x is conjugate to y and y is conjugate to z then $uxu^{-1}= y$ and $vyv^{-1}= z$. Then $v(uxu^{-1})v^{-1}= (vu)x(vu)^{-1}= z$ so x is conjugate to x).