Any ideas?
f(x) belongs to F[x] and alpha is root of f(x) is some field extension of F. Show irreducible poly. g(x) belonging to F[x] has property that h(x) belonging to F[x] also has alpha as a root then g(x)/h(x) in F[x].
Letbe a field and
be its extension field. Let
be algebraic over
(how do we know it is algebraic?). Next define the evaluation homomorphism:
. We know that the
is a principal ideal. So
for some
. This polynomial
must be of minimial degree because otherwise if
is smaller degree then we require that
for some
because the ideal is principal. But that is a contradiction because
. Thus,
is of minimal degree. Next we claim that
is irreducible because if not
and so one of the polynomial has the property that (WLOG)
but that cannot be because
has a smaller degree.
So we see that all the polynomial having this zero, i.e.are generated by an irreducible polynomial
. And so if
then
for some
. This shows that
divides
.
1)Okay define.
2)Convince yourself that.
3)Sinceis a PID it follows
for some
.
4)Use a similar argument as above.
Note, this is basically the same approach except kernels eliminate the need to prove #1 which is a little lengthy but straightforward checking of the field axioms.