There is nothing to do.
The fact the plane contains gives the answer away.
I have a problem that I really don't know how to solve. I have a regular 3 dimensions axis (x,y,z) with the center C(0,0,0) and 2 points, A(x1,y1,z1) and B(x2,y2,z2).
How can I calculate the intersection of the plane defined by A, B and C with the x,y,z axis in this last one?
Please give me a mathematical formula - if possible - without matrices; I'm not very good at that...
You already know three points in the plane: , , and . It would be simplest of course to let .
To find a vector perpendicular to the plane, find two vectors in the plane, say and , and take their cross product.
Hi again Plato,
That's obvious. But what I need to know is this: imagine a circle or an elipse or a rectangle, with center at (0,0,0) that passes through A and B. Where's does intercepts - the line - in x,y,z (alias in x,y)?
I've solved the problem of the plane equation and the xy line equation for the interception Now I have a bigger problem...
The plane has an inclination - how do I calculate that? And even worst, how do I calculate the line that goes through that maximum inclination?
Can someone help me out?