Lie Algebra-Roots and Dynkin basis

Given a Lie algebra I understand all the stuff about the Cartan-Weyl basis, the roots and stuff, so for example, for A2, the roots are

$\displaystyle \alpha=(1,0), \ \ \beta=\frac{1}{2}(-1,\sqrt{3}),\ \ \gamma=\frac{1}{2}(1,\sqrt{3})$

with simple roots $\displaystyle +\alpha$ and $\displaystyle +\beta$. The scalar products are

$\displaystyle (\alpha,\alpha)=1,\ \ (\beta,\beta)=\frac{-1}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{3}}{2}=1$ and $\displaystyle (\alpha,\beta)=-\frac{1}{2}$ using the definition of the scalar product in this basis from which one calculates the Cartan matrix and angles between roots blah blah blah...

I am reading 'Symmetries, Lie Algebras and Representations: A Graduate Course for Physicists' By Jürgen Fuchs, Christoph Schweigert and I do not understand the Dynkin basis. It says the quadratic form matrix is given by

$\displaystyle G_{ij}=(\Lambda_{(i)},\Lambda_{(j)})$ and $\displaystyle G^{ij}=(\check{\alpha}^{(i)},\check{\alpha}^{(j)}) =\frac{2}{(\alpha^{(i)},\alpha^{(i)})}A_{ij}$

where $\displaystyle A^{ij}$ is the cartan matrix, $\displaystyle \check{\alpha}$ is the co-root $\displaystyle \check{\alpha}=\frac{2\alpha}{(\alpha,\alpha)}$ and $\displaystyle \Lambda$ is the weight in the dual space with $\displaystyle \Lambda_{(i)}(\check{\alpha}^{(j)})=\delta_i^j$. From this, they claim $\displaystyle (\check{\alpha}^{(j)})_i=(\Lambda_{(i)})^j=\delta_ i^j$ and the Dynkin basis is

$\displaystyle (\alpha^{(i)})^j=A^{ij}$.

How does one calculate the matrix elements $\displaystyle G_{ij}$? It seems a recursive definition of $\displaystyle G_{ij}$ because it is written in terms of the inner product but to define the inner product in this basis one needs to already know $\displaystyle G_{ij}$

Does my confusion make sense to anyone and could someone please clear this up for me?