# L2 inner product means

• Dec 10th 2010, 02:22 AM
dervast
L2 inner product means
Hello everyone,
I would be grateful if you can help me understand what is the physical meaning of the inner product of two functions (L2-inner product)

I would like to thank you in advance for your help

Regards

Alex
• Dec 10th 2010, 02:46 AM
Ackbeet
Well, in quantum mechanics, it's used to compute the expectations of observables. Let's say you have a Hermitian operator $\displaystyle \hat{A}$ corresponding to some observable. You have already solved the Schroedinger equation for $\displaystyle \psi.$ What do you do? You form the $\displaystyle L^{2}$ inner product

$\displaystyle \langle\psi|\hat{A}\psi\rangle.$

This gives you the expected value from measuring the observable $\displaystyle \hat{A}.$
• Dec 10th 2010, 04:04 AM
CaptainBlack
Quote:

Originally Posted by dervast
Hello everyone,
I would be grateful if you can help me understand what is the physical meaning of the inner product of two functions (L2-inner product)

I would like to thank you in advance for your help

Regards

Alex

It's meaning is analogous to a (or the usual) inner product on a finite dimensional vector space.

Alternatively it is the un-normalized cross correlation of the two functions.

(function spaces are not physical so strictly speaking no physical meanings)
• Dec 16th 2010, 04:39 AM
dervast
I would like to thank you all for your contribution . I ll post back again if needed.
Regards
Alex
• Dec 16th 2010, 04:43 AM
Ackbeet
You're certainly welcome for my contribution.
• Jan 17th 2011, 04:35 AM
dervast
Dear all,
I would like also to check if I understood this correctly:
1. So If I got it right the inner product gives u a good feeling of what you expect (or what might be the result/outcome of a system that you study).
2. When I have the inner product of a function space the outcome is another function which
shows what to expect as outcome (regarding the specific domain range).

Do you agree?
Best Regards Alex
• Jan 17th 2011, 04:40 AM
Ackbeet
1. In the particular context of quantum mechanics, the inner product gives you expectation values, or the most probable value for measuring any particular observable. In other contexts, the interpretation of the inner product is different. For example, in normal 3D space, the inner product is the dot product (at least, it is in its most common definition), and is something of a measure of how much two vectors are pointed in the same direction.

2. The outcome of an inner product is a scalar, just like with its special case, the dot product. It is not another function or vector.
• Jan 17th 2011, 05:59 AM
HallsofIvy
Just to add my curmudeonly point: You should understand that mathematics is NOT physics and mathematical concepts do not have specific "physical meanings" associated with them. They can, of course, have applications to physics, as in the quantum mechanical application that Ackbeet mentioned, and, in those applications, have a specific "physical meaning".
• Jan 17th 2011, 06:12 AM
dervast
Quote:

Originally Posted by HallsofIvy
Just to add my curmudeonly point: You should understand that mathematics is NOT physics and mathematical concepts do not have specific "physical meanings" associated with them. They can, of course, have applications to physics, as in the quantum mechanical application that Ackbeet mentioned, and, in those applications, have a specific "physical meaning".

I am happy you clarified that. Sometimes I find myself trying to understand the physical meaning of 'something' as this sometimes give me a simple answer to " Why do we do that? " -or- "Why there was the need to invent this?"

Regards
Alex
• Jan 18th 2011, 09:19 AM
HallsofIvy
One of the interesting things about mathematics is that, once you have "invented" something to solve one problem, you find that it can be used to solve problems in many different fields. Newton and Leibniz invented Calculus to study problems in mechanics or, even more specifically, the movements of the planets. But now it is used in Biology, Economics, and even more distant fields. But if you are primarily interested in Physics, you are welcome to think about the "physical meaning" (perhap better- "physical application") of a mathematical concept.