So I know that a transformation is linear if T(u+v) = T(u) + T(v) and T(kv) = kT(v).

I'm given a system

y1 = b - c

y2 = ac

y3 = a - b

and to be honest I have no idea where to start.

Any help is appreciated.

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- December 7th 2010, 03:48 PMLord VoldemortBasic Linear Algebra - Linear Transformations Help
So I know that a transformation is linear if T(u+v) = T(u) + T(v) and T(kv) = kT(v).

I'm given a system

y1 = b - c

y2 = ac

y3 = a - b

and to be honest I have no idea where to start.

Any help is appreciated. - December 7th 2010, 03:56 PMdwsmith
Are you trying to determine if are each a linear transformation?

- December 7th 2010, 04:03 PMLord Voldemort
No, I think it's referring to the system as a whole. Maybe interpreted as a matrix? I'm not quite sure. My book is somewhat vague on this topic so I really quite confused.

EDIT: The answer in the back of the book says non-linear, so yes, I'd assume it's referring if the whole taken as a transformation is linear. - December 7th 2010, 04:23 PMdwsmith

- December 7th 2010, 04:38 PMLord Voldemort
Thank you very much!

For some reason it never occurred to me to just pick another set of points to prove/disprove it.

Now, I also have the system

y1 = 2b, y2 = 3c, y1 = a ,

Am I correct in saying that this is linear b/c

2b + 2y = 2(b+y), 3(c + z) = 3c + 3z, and so forth?

Also, considering the system

y1 = 2x, y2 = x + 2, y3 = 2x, I'm confused again...

y1 = y3 clearly are linear, and I'm a little confused about proving how y2 is/isn't. - December 7th 2010, 04:49 PMdwsmith
- December 7th 2010, 04:59 PMLord Voldemort
I'm not quite sure what an affine transformation is yet, is it just a nonlinear one?

(In regards to your last explanation)

Basically, y2 adds two to the the value input, but because adding two to both values and then adding the values as compared to adding the values as one value in and of itself and then adding two to that results in an inequality, it's not linear?

I guess I didn't really know how to approach the issue.

Thanks so much, I was a bit unclear on this but I definitely get this now!