# Subgroups and Intersection of Normal Subgroups

• Dec 1st 2010, 08:01 PM
kathrynmath
Subgroups and Intersection of Normal Subgroups
Prove that if N is a normal subgroup of G and H is any subgroup of G, then H intersect N is a normal subgroup of H.

N is normal so gng^-1 is in N for all n in N and g in G.
H is a subgroup so H is closed, has an identity, and has an inverse.

I don't know how to apply these definitions when thinking about the intersection
• Dec 1st 2010, 08:12 PM
Drexel28
Quote:

Originally Posted by kathrynmath
Prove that if N is a normal subgroup of G and H is any subgroup of G, then H intersect N is a normal subgroup of H.

N is normal so gng^-1 is in N for all n in N and g in G.
H is a subgroup so H is closed, has an identity, and has an inverse.

I don't know how to apply these definitions when thinking about the intersection

Let $\displaystyle h\in H$ be arbitrary. Note first that $\displaystyle h\left(N\cap H\right)=(hN)\cap (hH)$. To see this merely note that $\displaystyle x\in h\left(N\cap H\right)\Leftrightarrow x=hy\text{ }y\in H\cap N\Leftrightarrow x=hy\text{ }y\in N\text{ and }x=hy\text{ }y\in H\Leftrightarrow x\in hN\text{ and }x\in hH$. Similarly, $\displaystyle \left(N\cap H\right)h=(Nh)\cap (Hh)$.

Thus, we note that $\displaystyle h\left(N\cap H\right)=(hN)\cap (hH)=(hN)\cap H=(Nh)\cap H=(Nh)\cap (Hh)=(N\cap H)h$.